If we call “super()” without any superclass Actually, nothing will be displayed . Since the class named Object is the superclass of all classes in Java. If you call “super()” without any superclass, Internally, the default constructor of the Object class will be invoked (which displays nothing).2 Tem 2019
Read moreWhat happens when you don’t use super () constructor?
If we call “super()” without any superclass Actually, nothing will be displayed . Since the class named Object is the superclass of all classes in Java. If you call “super()” without any superclass, Internally, the default constructor of the Object class will be invoked (which displays nothing).2 Tem 2019
Read moreWhat happens when you don’t use super () constructor?
If we call “super()” without any superclass Actually, nothing will be displayed . Since the class named Object is the superclass of all classes in Java. If you call “super()” without any superclass, Internally, the default constructor of the Object class will be invoked (which displays nothing).2 Tem 2019
Read moreWhat is the role of super statement in constructor?
The super keyword in Java is a reference variable that is used to refer parent class objects. The super() in Java is a reference variable that is used to refer parent class constructors . super can be used to call parent class’ variables and methods. super() can be used to call parent class’ constructors only.
Read moreWhat is the role of super statement in constructor?
The super keyword in Java is a reference variable that is used to refer parent class objects. The super() in Java is a reference variable that is used to refer parent class constructors . super can be used to call parent class’ variables and methods. super() can be used to call parent class’ constructors only.
Read moreWhy super is first in constructor?
Java enforces that the call to super (explicit or not) must be the first statement in the constructor. This is to prevent the subclass part of the object being initialized prior to the superclass part of the object being initialized .
Read moreWhy super is first in constructor?
Java enforces that the call to super (explicit or not) must be the first statement in the constructor. This is to prevent the subclass part of the object being initialized prior to the superclass part of the object being initialized .
Read more