There is an implicit call to super() with no arguments for all classes that have a parent – which is every user defined class in Java – so calling it explicitly is usually not required . However, you may use the call to super() with arguments if the parent’s constructor takes parameters, and you wish to specify them.
Read moreWhy super is first in constructor?
Java enforces that the call to super (explicit or not) must be the first statement in the constructor. This is to prevent the subclass part of the object being initialized prior to the superclass part of the object being initialized .
Read moreWhere super () can be used within a constructor?
Description. When used in a constructor, the super keyword appears alone and must be used before the this keyword is used . The super keyword can also be used to call functions on a parent object.
Read moreWhere super () can be used within a constructor?
Description. When used in a constructor, the super keyword appears alone and must be used before the this keyword is used . The super keyword can also be used to call functions on a parent object.
Read moreWhere super () can be used within a constructor?
Description. When used in a constructor, the super keyword appears alone and must be used before the this keyword is used . The super keyword can also be used to call functions on a parent object.
Read moreWhy is Super called in constructor?
What happens if we call “super()” in a constructor without extending any class, in java? A super keyword is a reference of the superclass object in Java . Using this, you can invoke the instance methods constructors and, variables, of a superclass.
Read moreWhy is Super called in constructor?
What happens if we call “super()” in a constructor without extending any class, in java? A super keyword is a reference of the superclass object in Java . Using this, you can invoke the instance methods constructors and, variables, of a superclass.
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