If you want to call a superclass constructor with an argument, you must use the subclass’s constructor initialization list . Unlike Java, C++ supports multiple inheritance (for better or worse), so the base class must be referred to by name, rather than “super()”.
Read moreHow do I call a super constructor in C++?
If you want to call a superclass constructor with an argument, you must use the subclass’s constructor initialization list . Unlike Java, C++ supports multiple inheritance (for better or worse), so the base class must be referred to by name, rather than “super()”.
Read moreHow do I call a super constructor in C++?
If you want to call a superclass constructor with an argument, you must use the subclass’s constructor initialization list . Unlike Java, C++ supports multiple inheritance (for better or worse), so the base class must be referred to by name, rather than “super()”.
Read moreCan Super be used in a constructor?
both this() and super() can not be used together in constructor . this() is used to call default constructor of same class.it should be first statement inside constructor. super() is used to call default constructor of base class.it should be first statement inside constructor.
Read moreCan Super be used in a constructor?
both this() and super() can not be used together in constructor . this() is used to call default constructor of same class.it should be first statement inside constructor. super() is used to call default constructor of base class.it should be first statement inside constructor.
Read moreDoes super class need constructor?
A subclass needs a constructor if the superclass does not have a default constructor (or has one that is not accessible to the subclass). If the subclass has no constructor at all, the compiler will automatically create a public constructor that simply calls through to the default constructor of the superclass.
Read moreDoes super class need constructor?
A subclass needs a constructor if the superclass does not have a default constructor (or has one that is not accessible to the subclass). If the subclass has no constructor at all, the compiler will automatically create a public constructor that simply calls through to the default constructor of the superclass.
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