Calling exactly super() is always redundant . It’s explicitly doing what would be implicitly done otherwise. That’s because if you omit a call to the super constructor, the no-argument super constructor will be invoked automatically anyway.
Calling exactly super() is always redundant . It’s explicitly doing what would be implicitly done otherwise. That’s because if you omit a call to the super constructor, the no-argument super constructor will be invoked automatically anyway.